-49x^2+63x-18=0

Solution for -49x^2+63x-18=0 equation:

-49x^2+63x-18=0

a = -49; b = 63; c = -18;
Δ = b2-4ac
Δ = 632-4·(-49)·(-18)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-21}{2*-49}=\frac{-84}{-98}
=6/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+21}{2*-49}=\frac{-42}{-98}
=3/7
$